Calculation of Sodium Monofluorophosphate for 1000 ppm Fluoride

To achieve a fluoride concentration of 1000 ppm using Sodium Monofluorophosphate (SMFP), you can calculate the required percentage based on the fluoride content of the molecule.

Calculation for 1000 ppm Fluoride

1. Fluoride Content in SMFP:
   The molecular weight of Sodium Monofluorophosphate ($Na_2PO_3F$) is approximately 143.95 g/mol, and the atomic weight of Fluorine (F) is approximately 19.00 g/mol.

   • Fluoride weight fraction = $19.00 / 143.95 \approx 0.132$ (or 13.2%).
   • This means 1 gram of pure Sodium Monofluorophosphate provides approximately 0.132 grams of Fluoride ion.

2. Target Concentration:

   • 1000 ppm (parts per million) is equivalent to 0.1% w/w of Fluoride ion in the final formulation.

3. Required Percentage of SMFP:

   • Calculation: $0.1\% / 0.132 = 0.7575\%$
   • Guideline: To obtain 1000 ppm of Fluoride, you should use approximately 0.76% of Sodium Monofluorophosphate.

Technical Guidelines for Formulation

• Solubility: Sodium Monofluorophosphate is highly soluble in water. It should be dissolved in the water phase of your formulation.
• pH Range: The stable pH range for this ingredient is 3.50 - 7.00. Maintaining the pH within this range ensures the stability of the monofluorophosphate ion and prevents premature hydrolysis.
• Usage in Oral Care: It is commonly used in toothpastes, mouthwashes, and oral sprays to strengthen enamel and prevent cavities (anti-caries).
• Regulatory Note: In many regions (including Thailand and the EU), the maximum allowable concentration of Fluoride in toothpaste for adults is typically 1500 ppm (0.15% as F). A level of 1000 ppm is a standard and effective concentration for anti-caries protection.

For more ingredients related to oral health, you may explore the Oral Care and Anti-caries categories.